Answers to Book 2 Extra Problems

1.    12/1 x   1/412/4 = 3

 

2.     3/3  –   2/3  =   1/3

 

3.     6/6  –   1/6  –   2/6  =   3/6

 

4.     2/3  x   2/6  =   4/18

 

5.     3/4  x   1/12  =   3/48

 

6.     Since you want to make twice as many cookies, you need twice as much sugar:   2/1  x   2/3 cup  =   4/3  cup

 

7.     Since you want to make three times as many cookies, you need three times the amount of vanilla:    3/1  x   1/2  teaspoon  =   3/2  teaspoon

 

8.     2/5  x   3/5  =   6/25

 

9.     First we have to find out what fraction of the m&m’s in the bowl are peanut m&m’s.  This is a subtraction problem because we were told that two-fifths of all the m&m’s are chocolate:  The fraction that are peanut m&m’s must be    5/5  –   2/5  =   3/5.  The fraction of these m&m’s that are yellow is one-fifth.  So the fraction of all the m&m’s in the bowl that are yellow peanut m&m’s is    1/5  x   3/5  =   3/25

 

10.    This is another subtraction problem.   The fraction representing all the m&m’s in the bowl is    25/25.  The fraction that is red chocolate is   6/25  (the answer to problem 8), and the fraction that is yellow peanut is   3/25  (the answer to Problem 9).  The remainder must therefore be:

25/25  –   6/25  –   3/25  =   16/25

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Extra Problems for More Practice