{"id":199,"date":"2015-03-03T15:05:11","date_gmt":"2015-03-03T15:05:11","guid":{"rendered":"https:\/\/www.learningwithkayla.org\/?page_id=199"},"modified":"2015-04-28T01:39:26","modified_gmt":"2015-04-28T01:39:26","slug":"answers-to-book-2-problems","status":"publish","type":"page","link":"https:\/\/www.learningwithkayla.org\/?page_id=199","title":{"rendered":"Answers to Book 2 Problems"},"content":{"rendered":"<p>1a. \u00a0\u00a0 [pmath]1\/4[\/pmath] X\u00a0 3 \u00a0 = \u00a0\u00a0 [pmath]3\/4[\/pmath]\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1g. \u00a0 \u00a0 [pmath]3\/7[\/pmath] + \u00a0 [pmath]2\/7[\/pmath] =\u00a0\u00a0 [pmath]5\/7[\/pmath]<\/p>\n<p>&nbsp;<\/p>\n<p>1b. \u00a0\u00a0 [pmath]1\/6[\/pmath] X \u00a0 [pmath]5\/7[\/pmath]\u00a0 =\u00a0\u00a0\u00a0 [pmath]5\/42[\/pmath]\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1h. \u00a0\u00a0 [pmath]9\/10[\/pmath] \u00a0 &#8211; \u00a0\u00a0 [pmath]5\/10[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]4\/10[\/pmath]<\/p>\n<p>&nbsp;<\/p>\n<p>1c. \u00a0\u00a0 [pmath]1\/5[\/pmath] X\u00a0\u00a0 [pmath]2\/3[\/pmath]\u00a0 =\u00a0\u00a0\u00a0 [pmath]2\/15[\/pmath]\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1i.\u00a0\u00a0\u00a0\u00a0 [pmath]5\/7[\/pmath] X\u00a0\u00a0 [pmath]2\/6[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]10\/42[\/pmath]<\/p>\n<p>&nbsp;<\/p>\n<p>1d.\u00a0 \u00a0[pmath]1\/8[\/pmath] X \u00a0\u00a0[pmath]2\/3[\/pmath]\u00a0 = \u00a0\u00a0 [pmath]2\/24[\/pmath] \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1j.\u00a0\u00a0 [pmath]3\/8[\/pmath] +\u00a0\u00a0 [pmath]7\/8[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]10\/8[\/pmath]<\/p>\n<p>&nbsp;<\/p>\n<p>1e.\u00a0\u00a0 [pmath]5\/6[\/pmath] &#8211;\u00a0\u00a0 [pmath]2\/6[\/pmath]\u00a0 = \u00a0\u00a0 [pmath]3\/6[\/pmath] \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1k.\u00a0 \u00a0[pmath]3\/4[\/pmath] X \u00a0[pmath]3\/4[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]9\/16[\/pmath]<\/p>\n<p>&nbsp;<\/p>\n<p>1f.\u00a0\u00a0 [pmath]1\/3[\/pmath] X\u00a0\u00a0 [pmath]1\/5[\/pmath]\u00a0 = \u00a0\u00a0 [pmath]1\/15[\/pmath] \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1l.\u00a0\u00a0 [pmath]4\/10[\/pmath] X\u00a0\u00a0 [pmath]10\/4[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]40\/40[\/pmath]\u00a0 =\u00a0\u00a0 1<\/p>\n<p>&nbsp;<\/p>\n<p>2.\u00a0\u00a0 [pmath]2\/12[\/pmath],\u00a0\u00a0\u00a0\u00a0 [pmath]4\/1[\/pmath]\u00a0 x\u00a0\u00a0 [pmath]2\/12[\/pmath]\u00a0 = \u00a0\u00a0[pmath]8\/12[\/pmath], \u00a0 \u00a0\u00a0[pmath]12\/12[\/pmath]\u00a0 &#8211; \u00a0\u00a0[pmath]8\/12[\/pmath]\u00a0 = \u00a0\u00a0[pmath]4\/12[\/pmath]<\/p>\n<p>&nbsp;<\/p>\n<p>3.\u00a0\u00a0\u00a0 [pmath]4\/20[\/pmath],\u00a0\u00a0\u00a0\u00a0 [pmath]5\/1[\/pmath]\u00a0 x\u00a0\u00a0 [pmath]4\/20[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]20\/20[\/pmath]\u00a0 =\u00a0\u00a0 1,\u00a0\u00a0\u00a0\u00a0 No<\/p>\n<p>&nbsp;<\/p>\n<p>4.\u00a0\u00a0\u00a0 [pmath]5\/16[\/pmath]\u00a0 +\u00a0\u00a0 [pmath]3\/16[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]8\/16[\/pmath],\u00a0\u00a0\u00a0\u00a0 [pmath]16\/16[\/pmath]\u00a0 &#8211;\u00a0\u00a0 [pmath]8\/16[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]8\/16[\/pmath]<\/p>\n<p>&nbsp;<\/p>\n<p>5.\u00a0\u00a0\u00a0 [pmath]2\/8[\/pmath]\u00a0 +\u00a0\u00a0 [pmath]2\/1[\/pmath]\u00a0 x\u00a0\u00a0 [pmath]2\/8[\/pmath]\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0 [pmath]2\/8[\/pmath]\u00a0 +\u00a0\u00a0 [pmath]4\/8[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]6\/8[\/pmath],\u00a0\u00a0\u00a0\u00a0 [pmath]8\/8[\/pmath]\u00a0 &#8211;\u00a0\u00a0 [pmath]6\/8[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]2\/8[\/pmath]<\/p>\n<p>&nbsp;<\/p>\n<p>6. \u00a0 \u00a0 [pmath]2\/16[\/pmath]\u00a0 + \u00a0\u00a0 [pmath]3\/16[\/pmath] \u00a0 + \u00a0 [pmath]4\/16[\/pmath]\u00a0 +\u00a0\u00a0 [pmath]6\/16[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]15\/16[\/pmath]<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1a. \u00a0\u00a0 [pmath]1\/4[\/pmath] X\u00a0 3 \u00a0 = \u00a0\u00a0 [pmath]3\/4[\/pmath]\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1g. \u00a0 \u00a0 [pmath]3\/7[\/pmath] + \u00a0 [pmath]2\/7[\/pmath] =\u00a0\u00a0 [pmath]5\/7[\/pmath] &nbsp; 1b. \u00a0\u00a0 [pmath]1\/6[\/pmath] X \u00a0 [pmath]5\/7[\/pmath]\u00a0 =\u00a0\u00a0\u00a0 [pmath]5\/42[\/pmath]\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1h. \u00a0\u00a0 [pmath]9\/10[\/pmath] \u00a0 &#8211; \u00a0\u00a0 [pmath]5\/10[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]4\/10[\/pmath] &nbsp; 1c. \u00a0\u00a0 [pmath]1\/5[\/pmath] X\u00a0\u00a0 [pmath]2\/3[\/pmath]\u00a0 =\u00a0\u00a0\u00a0 [pmath]2\/15[\/pmath]\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1i.\u00a0\u00a0\u00a0\u00a0 [pmath]5\/7[\/pmath] X\u00a0\u00a0 [pmath]2\/6[\/pmath]\u00a0 =\u00a0\u00a0 [pmath]10\/42[\/pmath] &nbsp; 1d.\u00a0 \u00a0[pmath]1\/8[\/pmath] X \u00a0\u00a0[pmath]2\/3[\/pmath]\u00a0 &hellip; <a href=\"https:\/\/www.learningwithkayla.org\/?page_id=199\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">Answers to Book 2 Problems<\/span> <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"open","template":"","meta":{"footnotes":""},"class_list":["post-199","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/www.learningwithkayla.org\/index.php?rest_route=\/wp\/v2\/pages\/199","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learningwithkayla.org\/index.php?rest_route=\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.learningwithkayla.org\/index.php?rest_route=\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.learningwithkayla.org\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learningwithkayla.org\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=199"}],"version-history":[{"count":10,"href":"https:\/\/www.learningwithkayla.org\/index.php?rest_route=\/wp\/v2\/pages\/199\/revisions"}],"predecessor-version":[{"id":250,"href":"https:\/\/www.learningwithkayla.org\/index.php?rest_route=\/wp\/v2\/pages\/199\/revisions\/250"}],"wp:attachment":[{"href":"https:\/\/www.learningwithkayla.org\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=199"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}