Answers
1. [pmath]1/6[/pmath] + [pmath]3/6[/pmath] = [pmath]4/6[/pmath] , [pmath]6/6[/pmath] – [pmath]4/6[/pmath] = [pmath]2/6[/pmath]
2. [pmath]4/8[/pmath] + [pmath]1/8[/pmath] = [pmath]5/8[/pmath], [pmath]8/8[/pmath] – [pmath]5/8[/pmath] = [pmath]3/8[/pmath]
3. [pmath]3/8[/pmath] + [pmath]4/8[/pmath] = [pmath]7/8[/pmath] , [pmath]8/8[/pmath] – [pmath]7/8[/pmath] = [pmath]1/8[/pmath]
4. [pmath]2/12[/pmath] + [pmath]4/12[/pmath] + [pmath]5/12[/pmath] = [pmath]11/12[/pmath] , [pmath]12/12[/pmath] – [pmath]11/12[/pmath] = [pmath]1/12[/pmath]
5a. [pmath]5/8[/pmath] 5b. [pmath]2/8[/pmath] 5c. [pmath]3/8[/pmath] 5d. [pmath]4/12[/pmath]
5e. [pmath]14/14[/pmath] = 1 5f. [pmath]6/7[/pmath] 5g. [pmath]3/5[/pmath] 5h. [pmath]5/12[/pmath]
5i. [pmath]9/10[/pmath] 5j. [pmath]3/12[/pmath] 5k. [pmath]3/10[/pmath] 5l. [pmath]4/12[/pmath]
Did you notice that 5b is the inverse of 5a? Inverses “undo” each other. That sounds funny, so let me explain: In 5a, you added two-eighths to three-eighths to get five-eighths. In 5b, you took the answer to 5a (five-eighths) and subtracted one of the things you added (three-eighths) to get the other thing you added (two-eighths). So we can say that 5b “undid” 5a. That’s pretty cool, isn’t it? I’ve got a lot more cool stuff in my other books. Oh, in my next book, you’ll meet my friend, Cleveland. He’s cool, too!